Hi guys!
Today we are going to cover a seemingly scary looking but a quite simple section of GRE Quant - ALGEBRA!
There are going to be a lot of questions that you will encounter in your GRE that have an application of algebraic concepts. But do understand that the questions might look tough, but the underlying concept is just simple algebra.
This post covers a part of algebra - Quadratic Equations. We have started with an overview of the topic followed by practice questions.
In the subsequent sections, we will be posting more in relation to the concept. So, sit tight and keep practicing!
Overview
A quadratic equation is an equation of the form
πS2
> T
π|S| > |T|
πST < 0
πST > 0
Answer: |S| > |T|
(2) If (x+3)2 = 225, which of the following could
be the value of x-1?
π13
π12
π-12
π-16
π-19
Answer: -19
(3) If 3t3 -7=74, what is t2-t?
π3
π6
π-3
π18
π9
Answer: 6
π1
π1/(x+y)
π1/2
πxy
π2xy
Answer: ½
(5) If x+y=-3 and x2+y2=12, what is the value of 2xy? (Numeric Entry)
Answer: -3
(6) (x-2)2+(x-1)2+x2+(x+1)2+(x+2)2
π5x2
π5x2+10
πx2+10
π5x2+6x+10
π5x2-6xy+10
Answer: 5x2+10
(7) If a=(x+y)2 and b=x2+y2 and xy>0, which f the following must be
true? Indicate all such statements.
πa=b
πa>b
πa is positive
Answer: a>b, a is positive
(8) The maximum height reached by a ball thrown straight up
into the air can be determined by the formula h = -16 vt + d, where t is the
number of seconds since it was thrown, v is the initial speed of the throw (in
feet per second), d is the height (in feet) at which the ball was released, and
h is the height of ball 1 seconds after the throw. Two seconds after a ball is
thrown, how high in the air is the ball if it was released at a height of 6
feet and a speed of 80 feet per second?
π96 feet
π100 feet
π102 feet
π134 feet
π230 feet
Answer : 102 feet
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